Beta-Minus Emission
Neutron-to-proton conversion and electron emission
Lesson 1476 of 4,500 · Nuclear Concepts: Radioactivity
Learning objectives
- Describe the nuclear change in beta-minus decay
- Balance a beta-minus equation using A and charge
Introduction
Alpha decay removes a four-nucleon cluster, but beta-minus decay changes one kind of nucleon into another. A neutron becomes a proton, and an electron and an electron antineutrino are emitted. The nucleus keeps the same total nucleon count while its proton number rises by one. This is why beta-minus decay can turn carbon-14 into nitrogen-14 without changing its mass number.
Core explanation
At the level of nuclear bookkeeping, the transformation is neutron → proton + electron + electron antineutrino. The electron is the beta-minus particle, written ⁰₋₁e or β⁻. The antineutrino is electrically neutral and has no nucleon number. The nucleon count remains one on both sides because a neutron has become a proton. Electric charge remains zero: a proton has +1 and the electron has −1, while the antineutrino has zero charge.
For a parent ᴬ ZX, the daughter has mass number A and atomic number Z + 1. Its neutron count falls by one because N = A − Z. The short equation ᴬ ZX → ᴬ Z₊₁Y + ⁰₋₁e displays mass-number and charge bookkeeping. A fuller equation includes the antineutrino, conventionally written ν̅ₑ. In school balancing exercises, neutrinos are sometimes omitted because they contribute neither A nor electric charge; do not infer from that omission that they do not exist.
Carbon-14 illustrates the change: ¹⁴₆C → ¹⁴₇N + ⁰₋₁e + ν̅ₑ. Carbon-14 has six protons and eight neutrons. Nitrogen-14 has seven protons and seven neutrons. The total nucleon count remains fourteen, while one neutron has changed into a proton. Charge bookkeeping gives 6 = 7 + (−1). Identifying nitrogen requires consulting atomic number seven, not guessing from the parent name.
The beta electron is created in the decay process; it is not an outer-shell electron that the atom happened to lose. An ordinary carbon atom can lose an electron chemically and become a carbon ion, but then its nucleus still has Z = 6. In beta-minus decay the parent nucleus changes to Z = 7. The daughter atom's surrounding electrons may rearrange afterward, yet that chemical adjustment is separate from the nuclear event.
Beta-minus decay is possible for some neutron-rich nuclides, but “neutron-rich” is a qualitative guide rather than a universal rule. Energy balance and nuclear structure decide whether the change can happen. Also, one neutron-to-proton conversion does not imply that every neutron in the parent can transform with equal effect; the nuclide's overall state determines its observed half-life and decay modes.
The emitted beta particles can have a range of kinetic energies rather than one fixed energy for every decay of a given nuclide. The antineutrino shares the available energy and momentum with the electron and recoiling daughter. This observation was historically crucial in understanding beta decay. It is enough here to know that the simple balanced equation accounts for A and charge but does not by itself calculate individual particle energies.
Because a beta-minus particle is an electron, it can ionise matter along its path and is deflected by electric or magnetic fields according to its negative charge. Shielding and exposure depend on energy and geometry; “beta radiation” alone does not specify a universal range. A detector's count rate also differs from the source's number of decays because detection is not perfectly efficient.
Step-by-step reasoning
1. Start with the parent's A and Z and identify beta-minus as the stated emission. 2. Keep A unchanged and add one to Z for the daughter. 3. Use the daughter Z to find its element symbol. 4. Write ⁰₋₁e and include ν̅ₑ when giving the fuller physical equation. 5. Check A and electric-charge entries, then explain which nucleon changed.
Visual explanation
Draw a parent nucleus containing one highlighted neutron. Show that dot changing to a proton dot while an electron arrow and an antineutrino arrow leave the nucleus. Label the parent “A, Z” and the daughter “A, Z + 1.” A separate electron cloud outside the nucleus helps show that the emitted beta electron was produced in the nuclear event.
Real-world analogy
Imagine a team where one member changes role without anyone joining or leaving the team. The total number of members stays constant while the count in one role rises by one. That resembles unchanged A and increased Z. The analogy does not explain particle creation, antineutrinos or energy sharing.
Real-world example
Carbon-14 undergoes beta-minus decay and is used in radiometric dating of once-living material. The method relies on the statistical decrease of carbon-14 in a sample after exchange with the environment ends. The decay equation tells us that each transformed carbon-14 nucleus becomes nitrogen-14, not another carbon isotope.
Why?
Why does the daughter have the same mass number even though a particle leaves? Mass number counts protons plus neutrons, and the beta electron is not a nucleon. One neutron is replaced by one proton, so the total number of nucleons stays the same. The actual masses and energy do change; “same A” does not mean identical mass in kilograms.
Common misconception
“Beta-minus decay means an atom loses one of its existing electrons.” The emitted beta electron is generated during a nuclear neutron-to-proton transformation. An atom that merely loses an orbital electron becomes an ion of the same element; beta-minus decay raises nuclear Z and makes a new element.
Worked example
Phosphorus-32 has A = 32 and Z = 15 and undergoes beta-minus decay. Keep A = 32 and increase Z to 16. Element 16 is sulfur, so the daughter is sulfur-32. Write ³²₁₅P → ³²₁₆S + ⁰₋₁e + ν̅ₑ. The mass-number check is 32 = 32 + 0 + 0. The charge-number check is 15 = 16 − 1 + 0. The parent has 32 − 15 = 17 neutrons; the daughter has 32 − 16 = 16, consistent with one neutron becoming a proton.
Quick check
1. What daughter follows beta-minus decay of ³H, whose A = 3 and Z = 1? Answer: A remains 3, Z becomes 2, so the daughter is ³₂He, helium-3.
Exam focus
State that beta-minus emission raises Z by one and leaves A unchanged. Balance the electron's charge-number entry as −1, and explain that the beta electron originates in the nuclear transformation rather than the atom's electron cloud.
Advanced insight
At a deeper level, beta-minus decay is mediated by the weak interaction: a down quark in a neutron changes to an up quark, turning the neutron into a proton. This account explains why beta decay differs from alpha emission. It does not change the introductory bookkeeping rules, which remain the efficient way to find a daughter nuclide.
Summary
Beta-minus decay converts a neutron into a proton and emits an electron and an antineutrino. The daughter keeps A and has Z one higher. The electron is created in the nuclear event, and the full equation conserves nucleon count, electric charge, energy and momentum.
Practice questions
1. Complete ¹⁴₆C → ? + ⁰₋₁e + ν̅ₑ. Answer: The daughter is ¹⁴₇N, because A stays fourteen and Z rises from six to seven. 2. A beta-minus parent has A = 40 and Z = 19. What are the daughter's A and Z? Answer: A = 40 and Z = 20, so the daughter is calcium-40. 3. Why is an emitted beta electron different from an electron lost during ionisation? Answer: Beta emission accompanies a neutron-to-proton nuclear change and raises Z; ordinary ionisation changes electron count without changing the nucleus.