Complex Formation by Transition Metals
Metal ions accepting donor pairs from ligands
Lesson 2144 of 4,500 · d- and f-Block Elements
Learning objectives
- Describe ligand-to-metal pair donation
- Assign charges and coordination numbers in simple complexes
Introduction
Transition-metal ions often bind molecules or ions that donate lone pairs. The resulting coordination complexes can differ in colour, magnetism and redox behaviour from an isolated-ion model. Complex formation therefore links simple Lewis acid–base pair donation with three-dimensional ligand arrangements around a metal centre.
Core explanation
In a coordination bond, a ligand provides an electron pair to a metal acceptor orbital in a simple donor–acceptor picture. Water can donate an oxygen lone pair; ammonia donates a nitrogen lone pair; chloride donates from chlorine. Once a complex is formed, all metal–ligand connections are part of its electronic structure, and calling one bond permanently “special coordinate” while others are ordinary can be misleading. Metal–ligand bonding often includes covalency as well as electrostatic attraction.
The complex ion [Cu(H₂O)₆]²⁺ contains a copper centre and six water ligands in a common octahedral description. Water is neutral, so Cu is formally +2. The coordination number is six because six donor oxygen atoms directly attach to copper. Do not count H atoms in water as metal donors; the metal–oxygen connections define the number. An outer counterion such as sulfate in a crystalline salt balances charge but is not automatically one of the six inner ligands.
In [Fe(CN)₆]⁴⁻, six cyanide ligands are each assigned −1, total −6. The complex charge is −4, so Fe has formal +2 oxidation state. Each CN⁻ is monodentate in this simple example, contributing one donor atom, giving coordination number six. The d count is then formally d⁶, but the cyanide field can change spin state relative to a water complex. Thus charge, coordination number and d occupation answer three distinct questions.
Some ligands attach through more than one donor atom. Ethylenediamine (en) has two nitrogens capable of coordinating to one metal and is bidentate; three en ligands can supply six donor atoms to a metal, giving coordination number six, not three. Such multidentate ligands can form chelate rings. The stability of a chelate relative to analogous separate monodentate ligands involves thermodynamic factors including entropy, not merely the number of drawn bonds.
Metal oxidation state, ionic size and accessible orbital environment help determine what complexes form. Ligand identity and solvent also matter. A metal ion can exchange water ligands for ammonia or chloride in solution, sometimes changing colour and magnetic behaviour. A complex formula states a species, not necessarily that it is the only species at every concentration and pH.
Complex formation can influence redox potentials by stabilising one oxidation state more than another. It can also change solubility, allowing a metal to remain dissolved under conditions where a simple salt might precipitate. The introductory donor–acceptor picture is useful, but crystal-field and molecular-orbital models are needed for detailed spectra and magnetism.
Step-by-step reasoning
1. Identify the metal and each ligand inside square brackets. 2. Assign ligand charges and solve for metal oxidation state. 3. Count donor atoms directly attached to the metal for coordination number. 4. Draw or infer a plausible geometry from that count and chemistry. 5. Keep counterions outside brackets distinct from coordinated ligands.
Visual explanation
Draw an octahedral metal with six water oxygen donors around it. Separately draw three bidentate en ligands as three loops contributing six N donor atoms, showing why ligand count and coordination number can differ.
Real-world analogy
A hub can connect to several cables; one cable with two plugs occupies two hub ports. A bidentate ligand is one molecule but contributes two donor attachments, so counting molecules alone misses coordination number.
Real-world example
Complexation is used in water analysis to bind metal ions with multidentate ligands such as EDTA. The resulting species' stability and colour or indicator behaviour allow concentration measurements under controlled conditions.
Why?
Why is [Fe(CN)₆]⁴⁻ formally Fe(II)? Six CN⁻ ligands contribute −6 in the charge ledger; Fe must contribute +2 to give the overall −4 complex charge, regardless of the detailed metal–ligand covalency.
Common misconception
“The number of ligand molecules always equals the coordination number.” A bidentate ligand contributes two donor atoms, so three such ligands can make coordination number six.
Worked example
Analyse [Co(NH₃)₆]³⁺. Six neutral NH₃ ligands donate through N, so coordination number is six. Their charge contribution is zero, leaving Co oxidation state +3. A simple first-row count gives Co³⁺ d⁶. The exact spin state requires ligand-field analysis; it is not settled by charge and coordination number alone.
Quick check
1. How many donor atoms attach to a metal bound by three bidentate en ligands? Answer: Six donor nitrogens, giving coordination number six.
Exam focus
Count donors rather than ligand molecules, and solve charges algebraically. Keep inner-sphere ligands inside brackets distinct from outer counterions. Do not derive colour solely from coordination number.
Advanced insight
Metal–ligand bonding can involve ligand-to-metal donation and metal-to-ligand back-donation in some complexes. The simple lone-pair picture introduces connectivity but does not capture all covalent and electronic effects.
Summary
Transition-metal complexes form when ligands donate electron pairs to a metal centre. Oxidation state comes from charge balance, coordination number from attached donor atoms, and detailed colour or magnetism from the resulting electronic structure.
Practice questions
1. What is Cu's oxidation state in [Cu(H₂O)₆]²⁺? Answer: +2, because water is neutral. 2. What is the coordination number in [Cu(H₂O)₆]²⁺? Answer: Six, from six oxygen donors. 3. What is Fe's oxidation state in [Fe(CN)₆]⁴⁻? Answer: +2. 4. Does a sulfate counterion outside the complex brackets automatically count as an inner ligand? Answer: No. Outer counterions balance charge but are not necessarily coordinated.