Diffusion Layers at Electrodes
Near-surface concentration profiles during current flow
Lesson 2567 of 4,500 · Advanced Electrochemistry and Kinetics
Learning objectives
- Describe how concentration varies with distance from an electrode when current flows
- Use Fick's first law with the Nernst diffusion-layer model to relate flux to current
- Explain how the diffusion layer grows with time in still solution and is held constant by stirring
Introduction
When an electrode consumes a reactant, it creates a small zone of depleted solution right next to its surface. Everything the electrode does next depends on how fast fresh reactant can cross this zone. The region is the diffusion layer , and its thickness, typically between a few micrometres and a fraction of a millimetre, controls the maximum current, the shape of voltammograms and the performance of electrolysers and sensors.
Core explanation
Why a concentration gradient forms. Suppose species O is reduced at an electrode. Every O ion reaching the surface is converted to R, so the surface concentration c O(0) falls below the bulk concentration c . Further from the electrode the solution is unaffected. Between the two, concentration rises from c O(0) to c , and product R shows the opposite profile, highest at the surface.
Diffusion delivers the reactant. With an excess of supporting electrolyte, migration of the electroactive ion is negligible, and close to the surface convection is weak. Transport is then dominated by diffusion, described by Fick's first law :
J = −D (dc/dx)
where J is the flux (mol m⁻² s⁻¹), D the diffusion coefficient (typically about 10⁻⁹ m² s⁻¹ for small ions in water) and dc/dx the concentration gradient. At steady state, all the flux arriving at the surface is converted, so the current density is:
j = nF D (dc/dx) at x = 0
The Nernst diffusion-layer model. In a stirred or flowing solution, convection keeps the bulk well mixed, but a thin stagnant layer persists next to the surface. Nernst simplified this by assuming a linear profile across a layer of thickness δ:
j = nF D (c − c(0))/δ
Vigorous stirring makes δ smaller (perhaps 10 μm), steepening the gradient and increasing the current; gentle stirring gives δ of perhaps 100 μm. The real profile is curved, but the model captures the key dependence on transport conditions.
Unstirred solution: a growing layer. In still solution, there is no convection to limit the layer. After the potential is stepped to a value that drives the surface concentration to zero, depletion spreads outwards and the layer thickens with time roughly as √(πDt). The current therefore decays according to the Cottrell equation :
j = nF c √(D/πt)
For D = 1 × 10⁻⁹ m² s⁻¹, the layer is about 56 μm thick after 1 s and about 0.56 mm after 100 s. Eventually natural convection, driven by density differences, disrupts growth.
Link to overpotential. The surface concentrations set the local Nernst potential. As current increases, c O(0) falls and c R(0) rises, shifting the electrode potential away from its bulk equilibrium value. This shift is the concentration overpotential.
Microelectrodes. For an electrode only a few micrometres across, diffusion becomes three-dimensional (hemispherical) rather than planar. The diffusion layer reaches a steady size comparable with the electrode radius within milliseconds, giving a steady current even without stirring.
Formulae
Fick's first law: J = −D dc/dx. Nernst layer: j = nFD(c − c(0))/δ. Diffusion length: about √(πDt). Cottrell equation: j = nFc √(D/πt). Steady current at a disc microelectrode of radius r: I = 4nFDc r.
Step-by-step reasoning
To estimate the current across a Nernst diffusion layer:
1. Convert bulk concentration to mol m⁻³ (1 mol dm⁻³ = 1000 mol m⁻³). 2. Decide the surface concentration from the electrode potential (zero if strongly driven). 3. Calculate the gradient (c − c(0))/δ. 4. Multiply by D to obtain the flux. 5. Multiply by nF to obtain the current density.
Visual explanation
Plot concentration against distance from the electrode. For reactant O, the curve starts low at the surface and climbs to the flat bulk value. For product R, it starts high and falls to zero. In the Nernst model both curves are straight lines meeting the bulk values at x = δ. In still solution, successive curves at 1 s, 4 s and 9 s reach twice and three times as far into the solution.
Real-world analogy
Imagine a crowd queuing at a food stall. Near the counter the queue is thin because customers are served as soon as they arrive; further back the crowd is dense. How fast the stall serves people depends on how quickly people can move through the thinned-out zone. Stewards who keep the crowd moving shorten that zone, just as stirring shortens the diffusion layer.
Real-world example
In copper electrorefining, high current densities would deplete Cu²⁺ at the cathode and produce rough, powdery deposits. Circulating the electrolyte thins the diffusion layer and keeps the surface concentration high enough for smooth, dense copper to deposit. Rotating-disc electrodes use the same principle in the laboratory to set δ precisely.
Why?
Why does the current fall with time in an unstirred solution? The concentration gradient at the surface gets shallower as the depleted zone spreads outwards. Since flux is proportional to the gradient, fewer reactant particles arrive per second, and the current decays as t^(−1/2).
Common misconception
"The diffusion layer is a physical film on the electrode." It is not a separate substance or coating. It is simply the zone of solution whose composition has been changed by the electrode reaction, and its edge is gradual rather than sharp.
Worked example
Question: Fe³⁺ (1.0 × 10⁻³ mol dm⁻³, D = 7.0 × 10⁻¹⁰ m² s⁻¹) is reduced at a stirred electrode with δ = 20 μm. Estimate the current density when the surface concentration is half the bulk value.
Reasoning: c = 1.0 mol m⁻³; c(0) = 0.50 mol m⁻³. Gradient = 0.50 ÷ 2.0 × 10⁻⁵ = 2.5 × 10⁴ mol m⁻⁴. Flux = 7.0 × 10⁻¹⁰ × 2.5 × 10⁴ = 1.75 × 10⁻⁵ mol m⁻² s⁻¹. j = 1 × 96 485 × 1.75 × 10⁻⁵ ≈ 1.7 A m⁻².
Answer: About 1.7 A m⁻² (0.17 mA cm⁻²).
Quick check
1. What happens to the thickness of the Nernst diffusion layer, and to the current, when stirring is increased? Answer: The layer becomes thinner, the concentration gradient steepens and the diffusion-controlled current increases.
Exam focus
Know Fick's first law, the Nernst diffusion-layer expression for current and the √t growth of the layer in still solution. Be ready to convert mol dm⁻³ to mol m⁻³ and to sketch concentration–distance profiles for reactant and product.
Advanced insight
For a rotating-disc electrode, the Levich analysis gives δ = 1.61 D^(1/3) ω^(−1/2) ν^(1/6), where ω is the angular velocity and ν the kinematic viscosity. The diffusion layer is uniformly thick across the whole disc surface, which is why rotating discs are favoured for quantitative kinetic studies.
Summary
Current flow depletes reactant and accumulates product near the electrode, creating a diffusion layer. Fick's first law links the surface gradient to the current. In stirred solution a steady Nernst layer of thickness δ forms; in still solution the layer grows as √(Dt) and the current decays by the Cottrell equation. Surface concentrations determine the concentration overpotential.
Practice questions
1. State Fick's first law and define each symbol. Answer: J = −D dc/dx, where J is flux, D the diffusion coefficient and dc/dx the concentration gradient. 2. Estimate the diffusion length √(πDt) after 25 s for D = 1.0 × 10⁻⁹ m² s⁻¹. Answer: √(3.14 × 1.0 × 10⁻⁹ × 25) ≈ 2.8 × 10⁻⁴ m, about 0.28 mm. 3. By what factor does the Cottrell current fall between 1 s and 16 s? Answer: A factor of four, since current is proportional to t^(−1/2). 4. Why does adding a supporting electrolyte simplify the analysis of diffusion layers? Answer: It carries most of the migration current, so the electroactive species moves mainly by diffusion.