Formal Charge in Mechanisms
Bookkeeping charged intermediates
Lesson 2724 of 4,500 · Organic Mechanisms and Named Reactions
Learning objectives
- Assign formal charges after electron flow
- Check conservation of total charge across a step
Introduction
Mechanism drawings often fail because an arrow changes bond count but the new formal charge is not updated. Formal charge is a bookkeeping tool that helps reveal such errors. A neutral oxygen with two ordinary bonds may become positive after forming a third; a carbonyl oxygen may become negative after receiving π electrons. Total charge must be conserved across each elementary step.
Core explanation
For an atom in a Lewis structure, formal charge equals its neutral valence electron count minus the sum of nonbonding electrons and half the bonding electrons. In a common organic shortcut, neutral oxygen with two bonds and two lone pairs has formal charge zero; oxygen with one bond and three lone pairs is usually −1; oxygen with three bonds and one lone pair is usually +1. A neutral nitrogen commonly has three bonds and one lone pair; four bonds often give +1. Carbon with three bonds and an empty orbital is a carbocation with +1.
When water attacks a carbocation, oxygen donates a lone pair to form a C–O bond. It now has three bonds and one lone pair, so the immediate product is an oxonium ion, not a neutral alcohol. A later base removes one O–H proton and the O–H bond electrons return to oxygen, restoring neutral two-bond oxygen. Skipping the charged intermediate may not change the final formula, but it hides the acid-base step and can violate charge conservation in the proposed sequence.
In nucleophilic attack on a carbonyl, the C=O π pair goes to oxygen. The carbonyl oxygen changes from neutral double-bonded O to singly bonded O⁻. If the nucleophile was negatively charged, it can become neutral after forming the new bond, keeping the total charge at −1 in the tetrahedral alkoxide product. If the nucleophile was neutral, a positive charge may arise on the donor atom as O becomes negative, giving a zwitterionic intermediate before proton transfer. The details depend on the attacking species, so draw it rather than copy one generic charge pattern.
Formal charge is not identical to partial charge. A carbonyl carbon can be electrophilic with δ⁺ yet still have formal charge zero. Labeling every electrophile C⁺ would incorrectly imply a free carbocation. Likewise, an oxygen can be δ⁻ in a polar C–O bond without bearing formal −1. Keep full formal charge symbols for electron-count changes and δ labels for bond polarisation.
Resonance contributors can place formal charge on different atoms while representing one delocalised species. Total charge stays the same in every valid contributor, and nuclei remain fixed. If one contributor of acetate is drawn with overall −1 and another with zero, an electron or proton has been lost, meaning it is not a resonance alternative. Valence and charge checks are therefore part of resonance drawing too.
Step-by-step reasoning
1. Redraw all atoms and bonds after each arrow set. 2. Count bonds and lone pairs at atoms whose electron environments changed. 3. Assign formal charges using valence-electron bookkeeping. 4. Add all formal charges and compare with total reactant charge. 5. Distinguish formal from partial charge and correct omitted proton transfers.
Visual explanation
Make a small oxygen table: one bond/three lone pairs/−1; two bonds/two lone pairs/0; three bonds/one lone pair/+1. Place examples from carbonyl addition and water attack beside it.
Real-world analogy
A ledger records every transfer between accounts. If a balance changes without a corresponding entry, the ledger is incomplete; formal charges reveal missing electron or proton steps.
Real-world example
A student draws neutral water attacking an alkyl carbocation and labels the three-bond oxygen neutral. Charge accounting reveals the missing positive charge before deprotonation.
Why?
Why can carbonyl carbon be electrophilic without formal +1? Oxygen polarises C=O toward itself, creating partial charge separation while the standard neutral Lewis structure retains formal charge zero.
Common misconception
“A δ⁺ label is interchangeable with a formal positive charge.” Partial polarity and formal electron-count bookkeeping represent different features and predict different intermediates.
Worked example
Hydroxide attacks formaldehyde. Start with OH⁻ overall −1 and neutral H₂C=O. Oxygen of hydroxide donates a pair to carbonyl carbon, becoming neutral after making a second bond. The C=O π electrons move onto carbonyl oxygen, giving that oxygen −1. The resulting HO–CH₂–O⁻ tetrahedral species still has total charge −1, matching the reactants. Omitting the C=O arrow would give carbon too many bonds and an inconsistent charge picture.
Quick check
1. What formal charge usually belongs on oxygen with three bonds and one lone pair? Answer: +1, as in an oxonium intermediate.
Exam focus
Audit charge after every mechanism step. Use partial-charge symbols only for polarisation and do not silently neutralise a charged intermediate.
Advanced insight
Formal charges are model-dependent assignments in Lewis structures, while actual electron density is distributed continuously. The bookkeeping remains powerful because it constrains valid arrows and valence.
Summary
Formal charge tracks electron-pair redistribution through organic mechanisms. Correct assignments maintain valence and total charge, expose missing arrows, and distinguish true ions from merely polarised bonds.
Practice questions
1. What charge does carbonyl oxygen gain when C=O π electrons move onto it? Answer: It becomes formally −1 in the resulting alkoxide. 2. Does attack by neutral water directly produce a neutral alcohol from a carbocation? Answer: No. It first forms a positive oxonium ion that can deprotonate. 3. Must resonance contributors have the same overall formal charge? Answer: Yes. Resonance moves electrons but not protons or atoms between contributors.