Stepping Up: Adding One Carbon
Cyanide substitution, cyanohydrins and Grignard reaction with carbon dioxide
Lesson 2835 of 4,500 · Organic Conversions, Isomerism and Reasoning
Learning objectives
- Recognize three routes that introduce one carbon
- Track the new carbon from CN⁻ or CO₂
- Choose a route based on haloalkane versus carbonyl starting material
Introduction
A target with one more carbon than the starting compound requires a carbon source. Cyanide ion and carbon dioxide are common one-carbon inputs, but they attach through different mechanisms. Cyanide can replace a leaving group on an alkyl carbon or add to a carbonyl carbon as a cyanohydrin. A Grignard reagent can attack CO₂ and, after work-up, give a carboxylic acid. Atom mapping distinguishes the routes.
Core explanation
For a primary alkyl halide R–X, cyanide's carbon end can attack the carbon bearing X by SN2 and form R–C≡N. The carbon of the nitrile is a new carbon in the organic skeleton. Hydrolysing the nitrile gives R–COOH, again with that cyanide-derived carbon as the acid carbonyl carbon. Reducing the nitrile gives R–CH₂NH₂, with the added carbon as the CH₂ next to nitrogen. Thus one first step can branch toward an acid or an amine while preserving the extra carbon.
As an example, bromoethane CH₃CH₂Br has two carbons. CN⁻ substitution gives propanenitrile CH₃CH₂CN, with three carbons. Hydrolysis produces propanoic acid CH₃CH₂COOH; reduction produces propan-1-amine CH₃CH₂CH₂NH₂. Both products retain the cyanide carbon. This route is limited by SN2 accessibility: methyl and primary halides are most straightforward, secondary substrates can compete with elimination, and tertiary halides are poor choices for ordinary cyanide SN2 substitution.
A carbonyl compound can gain the same one-carbon cyanide unit by a different reaction. Cyanide attacks an aldehyde or ketone carbonyl carbon, moving C=O electrons to oxygen. Protonation yields a cyanohydrin, R₂C(OH)CN or RCH(OH)CN. The original carbonyl carbon becomes the OH-bearing carbon; the cyanide carbon is attached directly to it. Hydrolysis of the nitrile portion can give an alpha-hydroxy acid. This is nucleophilic addition , not replacement of a halogen, and the product retains the original carbonyl oxygen as OH.
For acetaldehyde, CH₃CHO, cyanohydrin formation gives CH₃CH(OH)CN. This three-carbon product can be hydrolyzed toward 2-hydroxypropanoic acid, CH₃CH(OH)COOH. The new carbon is again the nitrile or later acid carbon, while the aldehyde carbon becomes the carbon bearing OH. If one forgets that map, it is easy to draw 3-hydroxypropanoic acid instead and place OH on the wrong carbon.
The third method begins with an organomagnesium halide, RMgX, prepared from a compatible organic halide and Mg in dry solvent. Its carbon-bearing R fragment behaves as a strong nucleophile toward CO₂ carbon. The first product is a magnesium carboxylate, RCO₂⁻MgX⁺ in schematic form; acidic work-up yields RCOOH. CO₂ supplies the new acid carbonyl carbon. For ethylmagnesium bromide, CH₃CH₂MgBr, the product after CO₂ then acid is propanoic acid.
Grignard reagents require rigorous compatibility checks. Water, alcohols and carboxylic acids protonate or otherwise destroy the highly basic organomagnesium bond. A starting halide with an unprotected OH cannot simply be converted to RMgX and then carboxylated. The cyanide substitution route may be preferable for an accessible primary alkyl halide with incompatible acidic groups absent or protected, whereas Grignard carboxylation can work when SN2 substitution at the original halide carbon is unsuitable but organomagnesium formation is feasible.
These three routes all add one carbon but make different immediate functional groups: alkyl cyanide substitution gives a nitrile, carbonyl cyanide addition gives a cyanohydrin, and Grignard reaction with CO₂ gives a carboxylate. Choose by starting functional group and desired location of the new carbon, not merely by the arithmetic +1.
Step-by-step reasoning
Count carbons in start and target and mark the new target carbon. If it is an acid carbon next to an alkyl chain, consider R–X → RCN → RCOOH or RX → RMgX → RCOOH with CO₂. If target has adjacent OH and CN, consider cyanide addition to a carbonyl. For each route, identify whether the carbon source is CN⁻ or CO₂ and check SN2 sterics or Grignard compatibility.
Visual explanation
Draw three arrows with the added carbon coloured red: R–Br + CN⁻ → R–C≡N; R–CHO + CN⁻ → R–CH(OH)–C≡N; R–MgBr + CO₂ → R–C(=O)O⁻ → RCOOH. Keep the original R atoms black. The colour shows the same +1 count but three distinct attachment patterns.
Real-world analogy
Adding one room to a building can mean extending a hallway, attaching a side room or replacing an end cap with a larger entrance. CN⁻ substitution, cyanohydrin formation and CO₂ carboxylation each add one carbon but attach it at a different reactive site. The arithmetic is the same; the floor plan is different.
Real-world example
Phenylacetic acid, PhCH₂COOH, can be planned from benzyl bromide, PhCH₂Br, by cyanide substitution to PhCH₂CN followed by nitrile hydrolysis. The new acid carbon comes from cyanide. A separate feasible route for a compatible benzyl halide is organomagnesium formation followed by CO₂ and acid work-up, with CO₂ supplying that same target carbon.
Why?
Why does nitrile hydrolysis preserve the one-carbon gain? Hydrolysis changes the C≡N functional group into a carboxyl group; it does not detach the nitrile carbon from R. That carbon becomes the acid carbonyl carbon, so a two-carbon alkyl halide can yield a three-carbon carboxylic acid.
Common misconception
"Any +1-carbon method gives the same product arrangement." Cyanide addition to a carbonyl places OH on the original carbonyl carbon and CN beside it. Cyanide substitution on a haloalkane replaces X and gives no OH at that stage. CO₂ carboxylation requires a carbon nucleophile and gives a carboxylate.
Worked example
Question: Give two one-carbon-homologation routes from bromoethane to propanoic acid.
Reasoning: In route one, CN⁻ displaces Br to give propanenitrile; hydrolysis changes CN into COOH. In route two, Mg forms ethylmagnesium bromide; CO₂ reacts at its carbon, and acid work-up gives propanoic acid. The new carbon comes from CN⁻ or CO₂ respectively.
Answer: CH₃CH₂Br → CH₃CH₂CN → CH₃CH₂COOH, or CH₃CH₂Br → CH₃CH₂MgBr → CH₃CH₂COOH using CO₂ then acid.
Quick check
1. What carbon source becomes the acid carbon in Grignard carboxylation? Answer: Carbon dioxide supplies the new carboxyl carbon.
Exam focus
Circle the newly added carbon in the target and assign its reagent source. Distinguish SN2 cyanide substitution from carbonyl cyanide addition. Check haloalkane sterics for SN2, dry conditions for Grignard formation and acid work-up for neutral carboxylic acid.
Advanced insight
Two routes may reach the same acid but differ sharply in compatibility. A primary halide may be an easy cyanide SN2 substrate, whereas a hindered halide may fail there; a molecule with acidic OH may prevent Grignard formation unless protected. Route comparison must therefore include functional-group tolerance, not merely a successful carbon count on paper.
Summary
One-carbon homologation can use CN⁻ or CO₂. CN⁻ substitutes on an accessible alkyl halide to give nitrile, or adds to a carbonyl to give cyanohydrin. A Grignard carbon attacks CO₂ to give carboxylate then acid. All add one carbon, but their intermediate connectivity, conditions and limitations differ.
Practice questions
1. What three-carbon nitrile forms from bromoethane and CN⁻? Answer: Propanenitrile, CH₃CH₂CN. 2. Where is OH in the cyanohydrin from acetaldehyde? Answer: On the original aldehyde carbonyl carbon, adjacent to the new nitrile carbon. 3. What happens if water is added before a Grignard reagent reacts with CO₂? Answer: Water protonates and destroys the reactive C–Mg bond, preventing intended carboxylation. 4. What acid follows hydrolysis of propanenitrile? Answer: Propanoic acid, CH₃CH₂COOH, with the nitrile carbon retained.