Raman Activity from Character Tables

Polarizability derivatives and quadratic functions

Lesson 3629 of 4,500 · Advanced Quantum Chemistry and Group Theory

Learning objectives

Introduction

Raman spectroscopy observes inelastic scattering of light rather than direct vibrational absorption. Its leading vibrational activity criterion is a change in molecular polarizability as atoms move. Because polarizability is a tensor, its components transform like quadratic coordinate functions such as x², xy and yz. A character table therefore predicts Raman-allowed mode species from a different set of entries than those used for infrared activity.

Core explanation

An incident electric field induces a dipole approximately as μ ind = αE, with α the polarizability tensor. As a normal coordinate Q oscillates, a tensor component can vary as αij(Q) ≈ αij(0) + (∂αij/∂Q)₀Q + …. If the derivative is nonzero, the induced dipole contains oscillations at shifted frequencies and can scatter light with a vibrational Raman shift. A vibrational fundamental is symmetry-allowed in ordinary first-order Raman scattering when its mode species matches at least one quadratic function associated with a polarizability component.

The tensor's diagonal components transform like x², y² and z²; off-diagonal components transform like xy, xz and yz. In the C₂v convention E, C₂(z), σ(xz), σ(yz), x², y² and z² belong to A₁; xy belongs to A₂; xz to B₁; yz to B₂. Thus every C₂v irrep has at least one quadratic function. In ideal water, Γvib = 2A₁ + B₂, so all three normal modes are Raman allowed by symmetry as well as IR allowed. Their Raman intensities and polarisation behaviour still differ because the actual polarizability derivatives are not identical.

Infrared and Raman activities need not be mutually exclusive in a molecule without inversion symmetry. Water is a simple example: all its modes can satisfy both first-order tests. In a centrosymmetric molecule, however, dipole coordinates are ungerade under inversion while polarizability quadratics are gerade. A normal mode of definite parity cannot be both g and u, leading to the mutual exclusion rule for ideal centrosymmetric molecules: an IR-active fundamental is Raman-inactive and a Raman-active one is IR-inactive under the corresponding simple mechanisms.

Ideal CO₂ illustrates complementarity. Its symmetric stretch preserves inversion parity in a way that allows a polarizability change and gives a Raman band, while the asymmetric stretch and bending modes can change dipole moment and are IR active. A real spectrum may contain weak combination bands, overtones or effects from perturbations, so the rule should be stated for ideal first-order fundamentals rather than every observed feature at any frequency.

The Raman shift reflects a molecular vibrational energy difference. In Stokes scattering, the scattered photon has lower energy because the molecule gains vibrational energy; in anti-Stokes scattering, the scattered photon has higher energy because a thermally populated vibration loses energy. The selection-rule analysis for a fundamental focuses on which coordinate can change polarizability; it does not by itself tell the population ratio or absolute scattered intensity.

Polarisation can refine symmetry assignment. Different tensor components respond to different incident and scattered light polarisations, so an allowed mode can have a distinctive polarisation pattern. A totally symmetric vibration often changes diagonal polarizability components substantially, but the exact depolarisation ratio depends on tensor derivatives. Character-table allowance is a starting point, not a full intensity theory.

Step-by-step reasoning

Obtain each normal-mode symmetry at the equilibrium geometry. Read the character table's quadratic-function columns, keeping x², y², z² and cross terms distinct. Mark a mode Raman allowed if it matches any polarizability component. For a centrosymmetric molecule, check inversion parity and compare with the separate IR criterion. Finally distinguish predicted allowance from measured shift and intensity.

Visual explanation

Draw a molecule inside an incident electric field arrow. Show its electron cloud deforming more or less as a bond stretches, changing the induced dipole and creating shifted scattered light. Beside the sketch, make two small table columns: IR uses x,y,z; Raman uses x²,y²,z²,xy,xz,yz. A CO₂ symmetric-stretch drawing shows both bonds changing together and the electron cloud's ease of distortion changing.

Real-world analogy

An elastic ball can be easy or hard to deform depending on its shape. If a vibration rhythmically changes that ease, an applied force produces a modulated response. Raman activity similarly depends on changing electronic deformability, not directly on a permanent dipole. The analogy is mechanical and omits the optical scattering and tensor nature of polarizability.

Real-world example

Chemists often use Raman and IR spectra together because the techniques highlight different normal modes. An ideal symmetric stretch of CO₂ is a classic Raman-active, IR-inactive example, while asymmetric motion is prominent in IR. Joint interpretation can reveal whether a proposed molecular structure has an inversion centre or whether a perturbation has lowered its symmetry.

Why?

Why do quadratic coordinates appear in the Raman rule? Polarizability relates one vector, induced dipole, to another vector, electric field. Its tensor components transform like products of two coordinate directions. A mode matching one of those products can modulate that component and generate first-order Raman scattering.

Common misconception

Raman activity does not require a changing permanent dipole. It requires a changing polarizability. Nor are IR and Raman bands universally exclusive; exclusion is a special ideal rule for molecules with inversion symmetry. A mode allowed by both tests in water does not violate group theory.

Worked example

For C₂v water, use Γvib = 2A₁ + B₂. A₁ appears among x², y² and z², and B₂ appears as yz. Thus both A₁ modes and the B₂ mode match polarizability components and are Raman allowed. This result says nothing quantitative about which mode has the strongest line; calculating (∂αij/∂Q)₀ is needed for intensity.

Quick check

1. Which character-table functions give the ordinary Raman symmetry test? Answer: Quadratic coordinate functions corresponding to polarizability tensor components. 2. Can a non-centrosymmetric mode be both IR and Raman active? Answer: Yes. Water's C₂v modes provide examples of simultaneous symmetry allowance.

Exam focus

Contrast the derivatives (∂μ/∂Q)₀ for IR and (∂α/∂Q)₀ for Raman. Use the correct character-table columns and state the inversion condition before invoking mutual exclusion. Treat allowed as possible, not guaranteed strong.

Advanced insight

Raman intensity is governed by an effective second-order light–matter process and depends on incident wavelength, polarizability derivatives and experimental geometry. Near an electronic resonance, intensities can change dramatically and simple nonresonant comparisons may fail, while symmetry remains a valuable organisational framework with additional coupling considerations.

Summary

Raman-active fundamentals change molecular polarizability. Character tables test this through quadratic-coordinate species rather than the linear x,y,z functions used for IR. Water's C₂v modes are all Raman allowed, while centrosymmetric molecules exhibit ideal IR–Raman mutual exclusion for first-order modes. Frequencies and intensities require further calculation or measurement.

Practice questions

1. A mode is A₂ in C₂v. Can it be Raman active in the stated coordinate convention? Answer: Yes. The xy polarizability component transforms as A₂, so the mode passes the Raman symmetry test even though it does not match a linear dipole coordinate. 2. What happens to photon energy in Stokes Raman scattering? Answer: The scattered photon has lower energy than the incident photon because the molecule gains vibrational energy. 3. Why is ideal CO₂'s symmetric stretch Raman active but IR inactive in the basic model? Answer: It changes polarizability but does not produce a first-order dipole change; its even inversion parity supports Raman activity and excludes electric-dipole IR activity.