Carbon Monoxide Migratory Insertion
Conversion of metal alkyl and CO ligands into an acyl complex
Lesson 3754 of 4,500 · Organometallic Chemistry and Catalysis
Learning objectives
- Draw CO insertion into a metal–alkyl bond
- Track acyl connectivity and formal oxidation state
- Explain why ligand geometry and CO pressure influence the observed cycle
Introduction
Carbon monoxide can become the carbonyl carbon of an organic product when a metal-bound alkyl group and a coordinated CO combine. This elementary pattern is called CO migratory insertion . It creates a metal acyl, M–C(O)R, and features in carbonylation chemistry. The name may suggest that a free CO molecule wedges mechanically into a bond, but the useful picture begins with both reacting groups coordinated to the same metal in a suitable arrangement.
Core explanation
Write a simplified step as M–R + M–CO → M–C(O)R while recognising that it is one metal complex carrying R and CO. The R group migrates to the carbon of a coordinated CO ligand; the resulting acyl remains bound through its carbonyl carbon in the common representation. The carbon skeleton gains one carbon atom from CO. A methyl ligand therefore gives an acetyl ligand, M–C(O)CH₃, not M–O–CH₃. Keep atom labels on CO when tracing isotopes: the CO carbon becomes the acyl carbonyl carbon and CO oxygen becomes the acyl oxygen unless a later exchange occurs. Original organometallic teaching material places insertion among the central organometallic elementary steps; an ACS mechanistic study examines CO insertion in a metal carbonyl system.
In formal electron counting, an alkyl is X-type and CO is neutral L-type; the acyl is commonly treated as X-type. The metal's formal oxidation state therefore does not change in this elementary insertion, unlike oxidative addition or reductive elimination. Coordination number often decreases by one because two coordinated groups become one, though an external ligand can bind promptly to the opened site. Electron count may change in the unsaturated intermediate. These formal trends are useful for checking a cycle, but actual bonding includes metal-to-CO π backbonding and acyl resonance.
The R and CO ligands generally need to be cis or able to reach a suitable adjacent geometry for intramolecular migration. A trans geometry may require isomerisation first. CO can also bind a vacant metal site after migration, stabilising the acyl product. CO pressure may thus shift pre-equilibria or inhibit a site needed for a different step; one cannot deduce a simple first-order dependence on CO pressure for every catalyst. The reverse process, decarbonylation or deinsertion, can occur when conditions favour it. Productive carbonylation requires a follow-up step that releases an organic carbonyl compound and closes the catalyst cycle.
In methanol carbonylation routes to acetic acid, a metal alkyl/carbonyl intermediate is converted into an acyl and subsequent chemistry releases an acetate-derived product. The full industrial cycle also includes reagent activation, ligand substitutions and catalyst regeneration, so this insertion is a key step rather than the whole reaction. CO handling requires appropriate ventilation and monitoring because it is a poisonous gas; mechanistic discussion does not imply performing the experiment without professional equipment.
Step-by-step reasoning
1. Find a metal-bound alkyl and a coordinated CO in the same complex. 2. Verify or obtain an adjacent geometry for the reacting ligands. 3. Connect the alkyl carbon to the carbon of CO and retain the oxygen as C=O. 4. Draw the metal bound to the new acyl group and check formal oxidation state. 5. Consider CO re-coordination, reverse deinsertion and the next product-release step.
Visual explanation
Draw M with cis R and C≡O ligands. A curved arrow from the M–R bond toward the carbon of CO indicates migration; the product shows M–C(=O)–R. Highlight the new R–C bond in colour and label CO's C and O with isotope tags. Beside it draw an open coordination site that can bind an additional CO molecule.
Real-world analogy
Two ingredients are held at adjacent stations on one workbench; one is transferred onto the other, making a larger piece that remains held by the bench. The workbench does not become formally more or less oxidised just because the two pieces combine. The analogy clarifies adjacency and product connectivity but not orbital interactions.
Real-world example
An idealised methylmetal carbonyl complex can generate a metal acetyl species. Hydrolysis or another downstream reaction may turn the acetyl fragment into an acetic-acid derivative. Isotopically labelled ¹³CO can reveal whether the incoming carbonyl carbon is incorporated into the product, although isotope scrambling or exchange must be excluded for a definitive mechanistic assignment.
Why?
Why is formal metal oxidation state unchanged? Before insertion, R contributes one anionic X-type ligand and CO is neutral. After insertion, the acyl contributes one anionic X-type ligand. The formal charge assignment at the metal is therefore the same. The organic fragments change connectivity, but formal oxidation-state accounting tracks a different feature.
Common misconception
“CO inserts by first becoming a free carbon atom and oxygen atom” is false; the coordinated CO unit remains intact as a carbonyl group in the simple insertion picture. “Migratory insertion always raises metal oxidation state” confuses it with oxidative addition. “The methyl group bonds to oxygen” gives the wrong acyl connectivity.
Worked example
Start with a metal complex bearing –CH₂CH₃ and CO ligands. After CO migratory insertion, the organic group is –C(=O)CH₂CH₃ , a propionyl ligand. The carbonyl carbon is newly supplied by CO, so the alkyl fragment's two carbons become part of a three-carbon acyl fragment. If the metal was formally +2 before insertion under standard ligand assignments, it remains formally +2 after. This atom count is often more reliable than recalling a product name.
Quick check
1. What metal-bound group results from CO insertion into an M–CH₃ bond? Answer: An acetyl ligand, M–C(=O)CH₃, with the carbonyl carbon supplied by CO.
Exam focus
Draw the correct M–C(O)R connectivity and trace the CO carbon. State that metal formal oxidation state normally stays unchanged for this elementary step. Note the cis geometry requirement in the common intramolecular model. Distinguish insertion from later acyl cleavage that releases the final organic product.
Advanced insight
Rates can depend on the availability of a low-coordinate acyl intermediate and on how readily CO binds to it. Spectroscopic carbonyl stretching frequencies can monitor CO environments, but assigning one band to a particular intermediate requires supporting evidence. Pressure-dependent kinetics can reveal whether CO association or dissociation precedes the migrating step.
Summary
CO migratory insertion couples a metal-bound alkyl with coordinated CO to give a metal acyl. It adds one carbon to the organic fragment while usually leaving formal metal oxidation state unchanged. Geometry, ligand binding and reverse reactions determine whether the acyl proceeds to a useful carbonylated product.
Practice questions
1. What is the acyl fragment from an M–CH₂CH₃ group and CO? Answer: M–C(=O)CH₂CH₃, a propionyl group. 2. Does the CO oxygen normally become the oxygen of the acyl carbonyl in the simple step? Answer: Yes, absent later oxygen exchange. 3. How does formal metal oxidation state usually change during this insertion? Answer: It does not change, because one X-type alkyl becomes one X-type acyl. 4. Why might high CO pressure fail to speed an entire catalytic cycle monotonically? Answer: CO can stabilise an intermediate but also occupy a site needed for another substrate or step.