Thermodynamics of Intercalation Electrodes

Open-circuit voltage as a function of lithium content, lattice-gas models and voltage plateaus

Lesson 3982 of 4,500 · Advanced Electrochemistry and Energy Storage

Learning objectives

Introduction

An intercalation electrode stores lithium in a host rather than depositing all lithium as a separate metal phase. As lithium content changes, the host's chemical potential changes, and so does its equilibrium potential. The shape of an open-circuit voltage curve therefore contains thermodynamic information. A smooth slope can reflect changing site occupation in a solid solution; an extended plateau can reflect coexistence of phases at almost constant lithium chemical potential. The curve measured under current also contains kinetic and transport losses, so it must not be confused with true equilibrium voltage.

Core explanation

Consider an electrode host H with sites that can accept Li. A simplified insertion step is Li⁺(electrolyte) + e⁻(electrode) + H ⇌ Li–H . At equilibrium, the electrochemical potentials of reactants and product balance. Relative to Li metal, a useful conceptual relation is U(x) = [μ Li,metal − μ Li,host(x)]/F when chemical potentials are per mole of Li and signs are chosen for the host's reduction potential. Thus a lower host lithium chemical potential corresponds to a higher insertion voltage versus Li/Li⁺. In a full cell, the open-circuit voltage is the positive-electrode equilibrium potential minus the negative-electrode equilibrium potential at their respective states.

An ideal lattice-gas model treats host sites as equivalent with no interactions beyond exclusion. If x is the occupied fraction, its configurational contribution to lithium chemical potential is RT ln[x/(1−x)] . A corresponding idealised host potential contains a negative term −(RT/F) ln[x/(1−x)] , plus a reference potential. This expression slopes with x and becomes steep near the endpoints. Real materials have interactions, strain and ordered arrangements, so a regular-solution model may add an interaction term such as Ω(1−2x) to the chemical potential, with conventions depending on how Ω is defined.

If the free-energy curve is nonconvex over a composition range, a uniform intermediate composition can be less favourable than a mixture of Li-poor and Li-rich phases. At equilibrium, those phases share a common lithium chemical potential. Changing overall x then changes their proportions rather than the chemical potential much, yielding a voltage plateau in an ideal two-phase range. Finite particles, surface energy, coherent strain, temperature and defects can tilt or narrow the plateau. A plateau in a cycling curve can also be affected by overpotential and hysteresis, so slow-rate or relaxation measurements are needed for thermodynamic interpretation.

The area under a voltage-versus-charge curve relates to electrical energy, but using an equilibrium curve gives reversible energy under specified conditions. Delivered energy at nonzero current is smaller on discharge because of polarisation. The composition window also matters: a high theoretical lithium capacity may not be fully accessible without damaging the host or electrolyte.

Step-by-step reasoning

Specify whether the potential is versus Li/Li⁺ or is a full-cell voltage. Define x as lithium fraction in the particular host. Connect U(x) to lithium chemical potential, keeping the sign convention explicit. For an ideal solid solution, use the occupancy entropy to predict a slope. For a two-phase region, use equality of chemical potential to explain an approximately constant plateau. Finally distinguish the relaxed equilibrium curve from a charge/discharge curve measured under load.

Visual explanation

Draw free energy against x with a convex single-phase curve and its changing tangent slope. Below it draw a sloped U(x). Then draw a free-energy curve with a common tangent touching two compositions; compositions between them lie on mixtures of those phases. Below it draw a nearly flat voltage segment between the two coexistence compositions. Add a discharge curve lying below the equilibrium curve to show kinetic losses.

Real-world analogy

Imagine filling theater seats. When all seats are similar and occupancy is mixed, each additional person changes crowding gradually. If the audience instead forms two separated zones with nearly fixed local arrangements, increasing total attendance mainly changes how much of the theater belongs to each zone. This evokes a solid solution versus two-phase coexistence, though the real criterion is a free-energy construction.

Real-world example

Lithium iron phosphate is often described by a Li-poor/Li-rich two-phase picture over much of its operating range, giving a relatively flat voltage region under gentle conditions. Graphite has staged intercalation states and multiple features rather than one simple ideal-lattice slope. Measuring open-circuit potential after sufficient relaxation and comparing with diffraction can link voltage features to structural phase changes.

Why?

Why does voltage depend on lithium content? The free-energy cost of inserting the next lithium changes as sites fill and interactions evolve. Why can a plateau persist while capacity changes? Two phases can exchange material at a nearly fixed chemical potential while their relative amounts vary. Why does a practical cell deviate from the equilibrium curve? Current requires overpotential and creates concentration gradients.

Common misconception

A voltage plateau does not mean lithium concentration is unchanged throughout the electrode. In a two-phase model, total lithium content changes by varying the phase fractions. Another error is to infer an intrinsic thermodynamic plateau from a high-current voltage trace alone; polarisation and transport can alter the shape.

Worked example

Question: In the ideal lattice-gas term at 298 K, compare RT/F ln[x/(1−x)] at x=0.20 and x=0.80. Use RT/F≈0.0257 V.

Reasoning: At x=0.20, ln(0.20/0.80)=ln0.25≈−1.386, giving −0.0356 V. At x=0.80, ln4≈+1.386, giving +0.0356 V. The configurational chemical-potential term increases by 0.0712 F-volts per mole equivalent; because U contains its negative, the idealised electrode potential falls by about 0.071 V between these occupancies if other terms are unchanged.

Answer: The ideal mixing contribution changes from −0.0356 V to +0.0356 V, corresponding to a roughly 0.071 V drop in U under the stated convention.

Quick check

1. What changes across an ideal two-phase voltage plateau when the overall electrode lithium content increases? Answer: The relative fractions of Li-poor and Li-rich phases change while their common lithium chemical potential remains approximately fixed.

Exam focus

Define x, reference electrode and sign convention. Derive qualitative slope from μ = ∂G/∂n rather than memorising a curve. Distinguish equilibrium voltage from loaded voltage and include temperature when using RT/F. Describe plateaus through phase coexistence, not “no reaction.”

Advanced insight

The ideal lattice-gas end-point divergences signal a simplified model, not infinite physical voltage. Site energy distributions, ordering, interactions and finite capacity windows modify them. In small particles, interface and strain energies can suppress macroscopic phase separation or alter coexistence compositions. Even with the same equilibrium free energy, kinetic pathways can produce hysteresis between charge and discharge. Thermodynamic and dynamic models must therefore be compared using sufficiently relaxed data and structural probes.

Summary

Intercalation voltage reflects the lithium chemical potential of a host relative to a reference. An ideal distribution of site occupancies produces a sloping potential; two-phase coexistence can produce a plateau as phase fractions change. Real curves reflect interactions, strain and particle size, while measured curves under current additionally reflect kinetics and transport.

Practice questions

1. Write the simplified lithium insertion reaction into a vacant host site. Answer: Li⁺ + e⁻ + H ⇌ Li–H, with species and charges defined for the host.

2. Why is OCV measured after relaxation rather than immediately after stopping a high current? Answer: Concentration gradients and interfacial polarisation need time to relax toward equilibrium.

3. If two phases coexist at fixed temperature, what equilibrium quantity is equal between them for lithium exchange? Answer: Their lithium chemical potential is equal.

4. Does a high equilibrium voltage alone guarantee high delivered energy at high current? Answer: No. Ohmic, kinetic and transport polarisation reduce discharge voltage and may limit accessible capacity.

Sources: Thermodynamically consistent OCV models, Journal of Physical Chemistry Letters; Thermodynamic interpretation of battery voltage, Journal of Physical Chemistry C.