The Nuclear Landscape and the Chart of Nuclides

Reading N against Z, isotopes, isotones and isobars

Lesson 4072 of 4,500 · Nuclear and Radiochemistry

Learning objectives

Introduction

The periodic table organises elements by proton number, but it hides the fact that each element comes in many nuclear forms. The chart of nuclides fixes this by plotting every known nucleus on a grid of neutron number against proton number. It is to the radiochemist what the periodic table is to the synthetic chemist: a single map that shows at a glance which nuclei are stable, which decay, how they decay and what they become.

Core explanation

The axes. Each square on the chart represents one nuclide, labelled by its proton number Z and neutron number N. The usual convention, adopted by the major national data centres, places N on the horizontal axis and Z on the vertical axis. The mass number A = Z + N is not an axis but can be read along diagonals. A nuclide is written with its mass number as a superscript before the symbol, for example ⁵⁶Fe, which has Z = 26 and N = 30.

Rows, columns and diagonals. Three families of nuclides fall along straight lines:

Family What is shared Line on the chart (N horizontal, Z vertical) Example --- --- --- --- Isotopes Same Z Horizontal row ¹²C, ¹³C, ¹⁴C Isotones Same N Vertical column ¹⁴C, ¹⁵N, ¹⁶O (N = 8) Isobars Same A Diagonal running from upper left to lower right ¹⁴C, ¹⁴N, ¹⁴O

A useful memory aid: isotoPes share Protons, isotoNes share Neutrons and isobArs share A.

The stable band. Roughly 250 stable nuclides, shown as dark squares, form a narrow band. For light elements the band follows N ≈ Z: ⁴He, ¹²C, ¹⁶O and ⁴⁰Ca all have equal numbers of protons and neutrons. As Z rises, the band bends towards the neutron side. Iron-56 has N/Z ≈ 1.15 and lead-208 has N/Z ≈ 1.54. The extra neutrons dilute the growing electrostatic repulsion between protons without adding repulsion of their own. Above lead-208 and bismuth-209 (whose half-life is so long that it is effectively stable) there are no stable nuclides at all.

The unstable sea. More than 3000 radioactive nuclides have been observed on either side of the band. Nuclides below the band are neutron-rich; those above it are proton-rich. At the outer edges lie the drip lines , where the last nucleon is no longer bound. The proton drip line is well mapped; the neutron drip line is known only for light elements, and theory predicts several thousand more nuclides not yet made.

Decays as moves. Each decay mode corresponds to a fixed step on the chart. Beta-minus decay converts a neutron into a proton: N falls by 1 and Z rises by 1, a diagonal step along an isobar towards the band. Beta-plus decay and electron capture do the reverse. Alpha decay removes two protons and two neutrons, a diagonal jump of two squares down and two to the left. Gamma emission changes neither Z nor N, so the nuclide stays on its square. Nuclides therefore move towards the stable band until they reach it.

What each square records. A detailed chart gives, for each nuclide, the half-life or natural abundance, the decay modes with branching fractions, the principal radiation energies and sometimes the atomic mass and spin. Separate squares or sub-divisions show long-lived excited states called isomers.

Step-by-step reasoning

To locate and classify a nuclide such as ²³⁵U on the chart:

1. Read Z from the symbol: uranium has Z = 92. 2. Calculate N = A − Z = 235 − 92 = 143. 3. Find the column N = 143 and row Z = 92. 4. Its isotopes lie along row 92 (²³⁴U, ²³⁸U); its isobars lie along the diagonal A = 235 (²³⁵Np, ²³⁵Pa). 5. Compare N/Z (1.55) with the stable band to judge which decay modes are likely.

Visual explanation

Imagine a long dark ridge running diagonally across a grid, straight at first then curving towards the neutron axis. The ridge is the stable band. Pale squares cover its slopes on both sides, fading out at the drip lines. Arrows from each pale square point towards the ridge, showing the direction of decay.

Real-world analogy

The chart resembles a relief map of a valley. The stable nuclides lie along the valley floor, and radioactive nuclides sit on the valley walls. Water on a slope always runs downhill towards the floor; unstable nuclides always decay towards the stable band, releasing energy as they go.

Real-world example

Fission of uranium-235 produces fragments such as ⁹⁰Kr and ¹⁴⁴Ba, which keep roughly the uranium N/Z ratio of about 1.55. On the chart they lie far below the stable band for their smaller Z, which is why fission products are intensely radioactive and undergo long chains of beta-minus decays, stepping diagonally along isobars towards stability.

Why?

Why does the stable band bend away from N = Z? The strong nuclear force acts between all nucleons but has a very short range, whereas proton–proton repulsion is long-range and grows roughly as Z². In heavier nuclei, extra neutrons provide additional strong-force attraction without additional Coulomb repulsion, so stability requires N > Z.

Common misconception

"Isobars are the same element because they have the same mass." Isobars have the same mass number but different proton numbers, so they are different elements with different chemistry. ¹⁴C is a carbon atom and ¹⁴N is a nitrogen atom, despite sharing A = 14.

Worked example

Question: Classify each pair as isotopes, isotones or isobars: (a) ⁴⁰K and ⁴⁰Ar; (b) ¹³C and ¹⁴N; (c) ²³⁵U and ²³⁸U.

Reasoning: (a) Both have A = 40 but Z = 19 and 18 respectively. (b) ¹³C has N = 13 − 6 = 7; ¹⁴N has N = 14 − 7 = 7. (c) Both have Z = 92 but different A.

Answer: (a) isobars; (b) isotones; (c) isotopes.

Quick check

1. On a chart with N horizontal and Z vertical, along which line do all the isotopes of an element lie? Answer: Along a horizontal row, because every isotope of that element has the same proton number Z.

Exam focus

Examiners test the definitions of isotopes, isotones and isobars and ask you to predict the product of a decay by counting squares. State N and Z explicitly in every answer, and remember that the stable N/Z ratio rises from about 1 for light nuclei to about 1.5 for the heaviest.

Advanced insight

Pairs such as ³H and ³He, or ¹³C and ¹³N, are called mirror nuclei: the numbers of protons and neutrons are swapped. Their energy levels are almost identical, differing mainly by the Coulomb energy. This near-symmetry reflects the charge independence of the strong force, formalised as isospin, a concept that also underlies the asymmetry term in nuclear mass models.

Summary

The chart of nuclides plots N horizontally against Z vertically. Isotopes lie in rows, isotones in columns and isobars along diagonals of constant A. Stable nuclides form a narrow band that follows N ≈ Z for light elements and curves to N/Z ≈ 1.5 for heavy ones. Radioactive nuclides flank the band and decay towards it by fixed moves on the grid.

Practice questions

1. How many protons and neutrons are in ⁹⁰Sr (Z = 38)? Answer: 38 protons and 90 − 38 = 52 neutrons. 2. Name a nuclide that is an isotone of ¹⁶O (Z = 8, N = 8). Answer: Any nuclide with N = 8, for example ¹⁵N (Z = 7) or ¹⁴C (Z = 6). 3. Describe the move on the chart when ²¹⁰Po undergoes alpha decay, and name the product. Answer: Z falls by 2 and N falls by 2, a diagonal jump down and to the left, giving ²⁰⁶Pb (Z = 82, N = 124). 4. A neutron-rich fission fragment lies below the stable band. Which decay mode will it most probably undergo, and in which direction does it move? Answer: Beta-minus decay, moving diagonally along its isobar with Z increasing by 1 and N decreasing by 1, towards the stable band.