Word Equations for Displacement Reactions

A more reactive element taking the place of a less reactive one

Lesson 636 of 4,500 · Chemical Equations and Balancing

Learning objectives

Introduction

In a displacement reaction, one element replaces another in a compound. This is not a rearrangement that happens whenever two names are mixed: relative reactivity matters. Word equations allow the identities of the incoming element, the displaced element and the new compound to be checked before symbolic formulas are balanced.

Core explanation

A familiar metal example is iron + copper(II) sulfate → iron(II) sulfate + copper, under suitable conditions. Iron takes the place of copper in the sulfate-containing compound because of their relative tendency to form ions in this context. Copper is produced as an element, while sulfate remains associated with a different metal ion.

The metal's ionic charge must be known or specified where it can vary. Writing simply “iron sulfate” may leave ambiguity about iron(II) versus iron(III). A word equation with a Roman numeral carries information that later determines the correct salt formula.

Halogens can also displace one another from halide compounds. Chlorine + potassium bromide → potassium chloride + bromine is a standard pattern because chlorine is more reactive than bromine in the relevant group comparison. Bromine appears as elemental Br₂ in a later symbol equation, not as isolated neutral Br atoms.

The reverse combinations should not be assumed to proceed by the same simple pattern. Copper cannot generally displace iron from iron(II) sulfate under the ordinary classroom conditions represented by the example. Bromine does not displace chlorine from chloride in the same reactivity order. State the comparison rather than writing a product merely because the names fit a swap template.

The overall word equation does not show every ion in solution or each electron-transfer step. Some ions can remain spectators while one element is oxidised and another reduced. Later symbol and net ionic equations make that accounting more explicit.

Step-by-step reasoning

1. Identify the free element and the element currently present in the compound. 2. Compare their reactivities for the relevant metal or halogen displacement context. 3. If displacement is supported, name the new compound and liberated element precisely. 4. Check later formulas, elemental molecular forms and coefficients; if reactivity does not support the reaction, do not force the template.

Visual explanation

Draw a labelled compound card “potassium bromide” and a separate “chlorine” card. Show the outgoing cards as “potassium chloride” and “bromine,” with an arrow explaining that chlorine replaces bromine in the salt, while potassium remains in the salt.

Real-world analogy

A place in a team can be taken by a new participant under the team's rules, while the displaced participant leaves. The analogy captures replacement but not the chemical reason it happens; relative redox tendencies and solution conditions provide that explanation.

Real-world example

A reactive iron surface in a suitable copper(II) sulfate solution can lead to copper deposition and formation of iron(II) sulfate in the simplified account. Observing a reddish deposit supports a change, but the named reaction still needs the correct ionic charges and conservation checks.

Why?

Why is the reactivity comparison essential before writing products? The simple displacement pattern describes an energetically and chemically plausible direction for a particular pair. Reversing the participants can make the proposed equation balanced on paper without making it a reaction that occurs under the stated conditions.

Common misconception

“Displacement means any two ions exchange partners.” Single-element displacement involves an element replacing another in a compound. Two soluble ionic compounds exchanging ions are often described as double displacement or precipitation and require a different particle account.

Worked example

Given chlorine and sodium iodide, chlorine is more reactive than iodine in the familiar halogen ordering. Write chlorine + sodium iodide → sodium chloride + iodine. The later symbolic version is Cl₂ + 2NaI → 2NaCl + I₂. Both elemental halogens are diatomic, and the coefficients conserve sodium and halogen atoms.

Quick check

1. In iron + copper(II) sulfate → iron(II) sulfate + copper, which element is displaced? Answer: Copper is displaced from the sulfate-containing compound and appears as elemental copper.

Exam focus

Check the direction of the reactivity order and name the correct salt. Keep single-element displacement distinct from a reaction between two ionic compounds that exchange ions.

Advanced insight

Metal displacement can be described by coupled oxidation and reduction half-reactions. A standard potential comparison can help predict direction under defined conditions, but concentrations, complexation and kinetics can modify observations in real systems.

Summary

Displacement reactions replace one element in a compound with a more reactive suitable element. Metal and halogen examples require correct product naming and reactivity direction. A balanced symbol equation later checks atoms and charge, but chemical plausibility must be established first.

Practice questions

1. Write the word equation for chlorine displacing bromine from potassium bromide. Answer: chlorine + potassium bromide → potassium chloride + bromine. 2. Why should copper not automatically be written as displacing iron from iron(II) sulfate? Answer: The ordinary reactivity ordering does not support that displacement direction. 3. What detail is missing from the generic name “iron sulfate” in a variable-charge context? Answer: Whether the iron is in the +2 or +3 state, which determines the salt's formula.