Freezing-Point Depression

Delta Tf = Kf m and limits of the dilute model

Lesson 2045 of 4,500 · Solutions and Colligative Properties

Learning objectives

Introduction

When a solute remains mainly in the liquid rather than entering the solvent's crystal, the mixed liquid can stay stable down to a temperature below the pure solvent's freezing point. This is freezing-point depression. In a dilute nonelectrolyte model, the positive size of the drop is ΔTf = Kf m. The solution's actual freezing temperature is obtained by subtracting this drop from the pure-solvent freezing temperature.

Core explanation

Define ΔTf = Tf,pure − Tf,solution. The sign convention makes ΔTf positive for a lowered freezing point. For a dilute nonvolatile nonelectrolyte, ΔTf = Kf m, with m in mol kg⁻¹ solvent and Kf in °C kg mol⁻¹. For water, Tf,pure is 0.0 °C near 1 atm and Kf ≈ 1.86 °C kg mol⁻¹. A 0.500 m ideal nonelectrolyte solution therefore has ΔTf ≈ 0.930 °C and a predicted freezing point near −0.93 °C. Write both the positive depression and the negative final temperature to avoid a sign error.

The underlying equilibrium compares the chemical potential of solvent in the liquid with that of solid solvent. Dissolved solute lowers the liquid solvent's chemical potential relative to pure liquid, while a relatively pure solvent crystal excludes most solute. A lower temperature is then needed for the solvent's liquid and solid phases to balance. This explains why adding solute can keep liquid present below the normal freezing point without claiming that solute chemically destroys ice molecules.

This model assumes the solid that forms is essentially pure solvent. Some mixtures form solid solutions or other phases; their phase diagrams can be more complex. At high concentration, the linear Kf m relationship can fail, and a eutectic or other characteristic mixture composition may matter. A classroom formula should therefore be used for the stated dilute range, not extrapolated to arbitrary amounts of dissolved material.

For an electrolyte, an approximate expression is ΔTf ≈ iKf mformula. The ideal limiting i for NaCl is two and for CaCl₂ is three if fully dissociated into independent ions. At finite concentrations, effective factors can be smaller because ions interact. If the problem already gives the total molality of dissolved species , do not multiply by i again. The solvent-specific Kf does not change just because a different solute is used in the ideal dilute model.

Practical de-icing uses freezing-point depression but involves more than the equilibrium formula. Salt can lower the freezing point of water at a road surface, helping ice melt within suitable temperatures and concentrations. At very low temperatures, limited liquid water, finite solubility and eutectic behaviour can make a chosen salt ineffective. Environmental impacts, corrosion and application conditions also matter. The simple 1.86 × m calculation is an introductory comparison, not a complete road-treatment design.

Measured onset of crystallisation may differ from the equilibrium freezing point because liquid can supercool before a nucleus forms. During crystallisation, release of latent heat can cause the observed temperature to rise toward an equilibrium plateau. A laboratory should distinguish this kinetic delay from the thermodynamic freezing-point depression caused by solute.

Step-by-step reasoning

1. Identify pure-solvent Tf and Kf under the given conditions. 2. Convert solute amount to moles and solvent mass to kilograms. 3. Calculate molality; include an effective particle factor only if appropriate. 4. Calculate positive ΔTf = Kf m and subtract from Tf,pure. 5. Check for dilution, dissolved state, solid-phase behaviour and supercooling in observed data.

Visual explanation

Draw temperature horizontally with 0 °C at the pure-water freezing mark and a second mark at −0.93 °C for a 0.500 m ideal nonelectrolyte. An arrow pointing left is labelled ΔTf = 0.93 °C. Draw a small ice lattice containing water molecules only, beside a liquid solution containing both water and solute dots, to show that the simple model excludes solute from the solid.

Real-world analogy

If a group of dancers can form a precise pattern only when enough partners match, adding different participants can make the organised pattern harder to establish. Solute particles make formation of a pure solvent crystal less favourable relative to the mixed liquid. The analogy illustrates an equilibrium preference, not a physical obstruction that alone determines freezing.

Real-world example

A lab compares equal-molality glucose and sodium chloride solutions in water. Under an ideal dilute model, sodium chloride can produce about twice the freezing-point depression because it contributes roughly two ions per formula unit, while glucose remains one molecule. Actual measurements need an effective factor and control of supercooling, especially if one solution crystallises later than the other.

Why?

Why is Kf for water numerically different from water's Kb? Freezing and boiling involve different phase equilibria and thermodynamic properties of the pure solvent. Both constants depend on solvent identity, but they are not required to equal one another.

Common misconception

“The solution has ΔTf = −0.93 °C.” With the defined convention, ΔTf is a positive magnitude of 0.93 °C. The final aqueous freezing point may be −0.93 °C when pure water freezes at 0 °C.

Worked example

Dissolve 6.00 g of a nonvolatile nonelectrolyte with molar mass 120 g mol⁻¹ in 0.250 kg water. Solute moles = 6.00/120 = 0.0500 mol; molality = 0.0500/0.250 = 0.200 m. For water Kf = 1.86 °C kg mol⁻¹, ΔTf = 1.86 × 0.200 = 0.372 °C. The predicted freezing point is 0.000 − 0.372 = −0.372 °C under the dilute ideal assumptions. Solute mass is not divided by total solution mass in this formula.

Quick check

1. For ordinary freezing-point depression, is the final freezing point above or below the pure solvent's value? Answer: Below it; subtract the positive depression ΔTf from the pure-solvent freezing temperature.

Exam focus

Keep the sign convention explicit: ΔTf = Tf,pure − Tf,solution. Use solvent kilograms and the correct solvent's Kf. If an electrolyte is present, state whether i or effective particle molality has already been included.

Advanced insight

Freezing-point depression is a phase-equilibrium measurement and can estimate unknown molar mass, but nonideality and supercooling influence experimental interpretation. The first solid to form can change liquid composition as solvent leaves the liquid, so the later freezing path is not necessarily described by one fixed initial molality.

Summary

Nonvolatile solute generally lowers the equilibrium freezing temperature when the solid phase is mainly pure solvent. For dilute nonelectrolytes, ΔTf = Kf m is a positive drop and Tf,solution = Tf,pure − ΔTf. Electrolytes, concentration, phase behaviour and supercooling qualify the simple model.

Practice questions

1. Find ΔTf for 0.25 m ideal nonelectrolyte in water using Kf = 1.86 °C kg mol⁻¹. Answer: 1.86 × 0.25 = 0.465 °C. 2. What freezing point does that predict if pure water freezes at 0 °C? Answer: 0 − 0.465 = −0.465 °C under the ideal dilute model. 3. Why is a delayed first crystal not necessarily evidence of a lower equilibrium freezing point? Answer: The liquid may have supercooled because crystal nucleation was delayed.