Semiconductors and p–n Types
Electron and hole carriers from controlled doping
Lesson 2216 of 4,500 · The Solid State
Learning objectives
- Explain n-type and p-type silicon
- Describe carrier behavior at a p–n junction without claiming either region has net bulk charge
Introduction
Semiconductors become especially useful when their mobile-carrier populations can be deliberately changed. Group-15 dopants in silicon commonly make n-type regions with electrons as majority carriers; group-13 dopants make p-type regions with holes as majority carriers. Putting these regions together creates a p–n junction, the basis of diode behavior.
Core explanation
Pure silicon has a tetrahedral covalent network and a finite electronic band gap. At ordinary temperatures some electrons can be promoted into conducting states, leaving holes in valence states, but the intrinsic carrier population is modest. Substitutional phosphorus has one more valence electron than Si and can provide a donor level from which an electron becomes mobile. This yields n-type conduction when donors are activated.
Substitutional boron has one fewer valence electron than Si and can accept an electron from the network, leaving a mobile hole. This gives p-type behavior. A hole acts as a positive charge carrier because neighboring electrons can move to fill it, causing the vacancy in electron occupancy to propagate. It is not an empty atom site or a positively charged proton moving through the crystal.
Neither n-type nor p-type bulk silicon is grossly charged. Ionized donor or acceptor sites provide fixed charges that balance mobile carriers in the bulk. The letters n and p identify majority mobile carrier sign, not a net macroscopic negative or positive material. Minority carriers also exist and matter in junction operation.
At a p–n interface, electrons and holes diffuse across the boundary and recombine, leaving a region depleted of mobile carriers. Fixed ionized dopants in this depletion region create an internal electric field. Forward bias can lower the effective barrier for carrier injection, allowing substantial current; reverse bias generally widens the depletion region and suppresses ordinary current, although leakage and breakdown can occur.
This simplified picture explains a diode's direction preference but not every device detail. Temperature, dopant levels, junction geometry and defects influence current-voltage behavior. A solar cell or light-emitting diode uses a p–n junction in a different operating mode and material system. The p–n principle is shared, while absorption and emission details depend on band structure.
Carrier concentration is not identical to dopant concentration under all conditions. Some dopants are inactive, compensating dopants may be present, and temperature changes ionization and intrinsic carriers. Mobility can fall at high impurity concentration because scattering increases. Device design balances these effects rather than simply adding as much dopant as possible.
Step-by-step reasoning
1. Identify host silicon's four-valence-electron framework. 2. Compare substitutional dopant valence: group 15 donor, group 13 acceptor. 3. Name majority carrier: electron for n-type, hole for p-type. 4. At a junction, describe diffusion, recombination and depletion field. 5. Qualify bulk charge neutrality and nonideal device behavior.
Visual explanation
Draw adjacent p and n silicon regions with holes and electrons as mobile symbols. Near the boundary, show their recombination and a depletion zone containing fixed ionized dopant charges. Add forward- and reverse-bias arrows showing easier or harder carrier crossing.
Real-world analogy
One side of a hallway has extra movable tokens; the other has open token positions. At the border, tokens fill openings, leaving a zone that resists further movement. The analogy hints at depletion but real junction behavior follows electric fields and energy bands.
Real-world example
A silicon diode conducts much more readily in one bias direction than the other because its p–n junction changes carrier-injection barriers. The crystal contains small dopant fractions, yet the device-scale electrical response changes greatly.
Why?
Why is a hole mobile if no positive particle travels? Electrons can successively fill neighboring vacant valence states, making the empty-state position move through the lattice as an effective positive carrier.
Common misconception
“p-type silicon is positively charged overall.” It is approximately electrically neutral in bulk; p denotes holes as majority mobile carriers, balanced by fixed dopant charge.
Worked example
Classify silicon doped separately with P and B. P has five valence electrons versus Si's four, so activated P is a donor and electrons dominate mobile conduction: n-type. B has three, so it is an acceptor and holes dominate: p-type. Joining these regions gives a p–n junction. The answer requires identifying substitutional dopants; a layer of elemental phosphorus sitting on top of silicon is not automatically equivalent to doped silicon.
Quick check
1. What is the majority mobile carrier in p-type silicon? Answer: Holes.
Exam focus
Explain donor and acceptor valence counting, identify carriers, and state bulk neutrality. Describe junction depletion and directional current qualitatively without asserting perfect one-way conduction.
Advanced insight
Carrier diffusion and electric drift balance at an unbiased junction, producing a built-in potential. Device current under bias arises from altered carrier injection and recombination, quantified with semiconductor transport models.
Summary
Donor-doped silicon is n-type with electron majority carriers; acceptor-doped silicon is p-type with hole majority carriers. A p–n junction creates a depletion field and direction-dependent conduction while each bulk region remains nearly neutral.
Practice questions
1. Is phosphorus in substitutional silicon usually donor or acceptor? Answer: Donor, supplying an extra valence electron relative to Si. 2. What remains fixed in a depletion region after mobile carriers recombine? Answer: Ionized dopant sites, which create an internal electric field. 3. Does reverse bias guarantee exactly zero current in a real diode? Answer: No. Leakage and, at sufficient bias, breakdown can occur.