Carboxylic Acid Derivatives Overview
Acyl compounds and nucleophilic acyl substitution
Lesson 2338 of 4,500 · Aldehydes, Ketones and Carboxylic Acids
Learning objectives
- Recognise acid chlorides, anhydrides, esters and amides as acyl compounds
- Describe the addition–elimination mechanism of nucleophilic acyl substitution
- Rank derivatives by reactivity and explain the order using leaving-group ability and resonance
Introduction
Replace the OH of a carboxylic acid with another electronegative group and you get a carboxylic acid derivative . Acid chlorides, acid anhydrides, esters and amides all contain the same acyl group , R–C=O, and they all react by the same basic pathway: a nucleophile adds to the carbonyl carbon and then a group leaves. Aldehydes and ketones stop after addition; acyl compounds carry on to substitution. Understanding this one mechanism and one reactivity order explains most of their chemistry.
Core explanation
The family. Using ethanoic acid (CH₃COOH) as the parent:
Derivative General formula Example Group replacing OH --- --- --- --- Acid chloride RCOCl ethanoyl chloride, CH₃COCl –Cl Acid anhydride (RCO)₂O ethanoic anhydride, (CH₃CO)₂O –OCOR Ester RCOOR′ methyl ethanoate, CH₃COOCH₃ –OR′ Amide RCONH₂ ethanamide, CH₃CONH₂ –NH₂
Nitriles, RC≡N, are often grouped with them because they hydrolyse to acids, although they contain no carbonyl group.
Nucleophilic acyl substitution. The mechanism has two stages. First, a nucleophile attacks the electrophilic carbonyl carbon, the π bond breaks and the oxygen takes a negative charge, giving a tetrahedral intermediate . Second, the C=O double bond re-forms and a leaving group Y is expelled. The net result is RCOY + Nu⁻ → RCONu + Y⁻. In an aldehyde or ketone, the potential leaving groups would be H⁻ or R⁻, which are far too basic to leave, so the intermediate is simply protonated instead.
Reactivity order. The standard order is:
acid chloride > acid anhydride > ester ≈ carboxylic acid > amide
Two factors explain it:
1. Leaving-group ability. Good leaving groups are weak bases. Cl⁻ (conjugate base of HCl, pKa about −7) leaves very easily; carboxylate (pKa about 4.8) fairly easily; alkoxide (pKa about 16) poorly; amide ion NH₂⁻ (pKa about 38) very poorly. 2. Resonance donation. A lone pair on the atom attached to the acyl carbon can be shared with the C=O, reducing the positive character of the carbon. Nitrogen donates strongly, so amides are least electrophilic. Chlorine's lone pairs are in a larger 3p orbital and overlap poorly with carbon's 2p orbital, so acid chlorides get little stabilisation.
Interconversion rule. A more reactive derivative can be converted into a less reactive one directly, but not the reverse. Ethanoyl chloride reacts with ethanol to give an ester and with ammonia to give an amide, while an amide cannot be turned into an acid chloride by adding chloride ions.
Hydrolysis. All derivatives are hydrolysed by water to the parent carboxylic acid, but at very different rates: acid chlorides fume in moist air, esters need heating with acid or base, and amides need prolonged heating with strong acid or alkali.
Step-by-step reasoning
To predict the product of a nucleophilic acyl substitution:
1. Identify the acyl carbon and the group Y attached to it. 2. Identify the nucleophile (water, alcohol, ammonia, amine, hydroxide). 3. Add the nucleophile to the carbonyl carbon to form the tetrahedral intermediate. 4. Re-form C=O and expel the best leaving group. 5. Check the product is less reactive than the starting derivative; otherwise the reaction is unfavourable.
Visual explanation
Draw the acyl carbon as trigonal planar with the nucleophile approaching from above the plane. In the tetrahedral intermediate four groups surround carbon; then the O⁻ "pushes back" to re-form the double bond, and the arrow shows Y departing. The simulation of nucleophilic addition shows the first half of this sequence.
Real-world analogy
Think of the acyl group as a seat and Y as the person sitting on it. A newcomer (the nucleophile) squeezes in, making a crowded moment (the tetrahedral intermediate), then whoever holds on least tightly gets up and leaves. Chloride barely holds on; an amide nitrogen grips firmly.
Real-world example
Proteins are polyamides. Their peptide bonds are so resistant to hydrolysis that, without enzymes, a peptide bond in neutral water at room temperature has a half-life of hundreds of years. This stability comes directly from strong nitrogen lone-pair donation and the very poor leaving group, making amides the most robust acyl derivative.
Why?
Why do aldehydes add but acyl compounds substitute? After a nucleophile adds, the intermediate can only re-form the C=O bond if a group can leave. Acyl compounds carry groups such as Cl⁻ or RO⁻ that can depart, while aldehydes and ketones carry H or alkyl groups whose anions are too unstable to leave.
Common misconception
"Nucleophilic acyl substitution is like SN2, with the nucleophile displacing Y in one step." It is a two-step addition–elimination via a tetrahedral intermediate; the configuration at the acyl carbon is irrelevant because it is planar before and after.
Worked example
Question: Predict the organic product when ethanoic anhydride reacts with methanol, and name the leaving group.
Reasoning: Methanol adds to one acyl carbon; the tetrahedral intermediate re-forms C=O and expels ethanoate, a good leaving group. The ester is less reactive than the anhydride, so the reaction is favourable.
Answer: Methyl ethanoate, CH₃COOCH₃, with ethanoate (then ethanoic acid) as the by-product.
Quick check
1. Place ethanamide, ethanoyl chloride and ethyl ethanoate in order of decreasing reactivity towards water. Answer: Ethanoyl chloride, then ethyl ethanoate, then ethanamide.
Exam focus
Draw both steps of the mechanism with curly arrows, showing the tetrahedral intermediate with O⁻. Justify reactivity order using leaving-group basicity and lone-pair donation, and apply the rule that derivatives convert downhill in reactivity.
Advanced insight
Infrared spectroscopy tracks the resonance effect: C=O stretching frequencies are roughly 1800 cm⁻¹ for acid chlorides, about 1820 and 1760 cm⁻¹ (two bands) for anhydrides, about 1740 cm⁻¹ for esters and about 1650–1690 cm⁻¹ for amides. More donation from the attached atom gives the C=O more single-bond character and a lower frequency.
Summary
Carboxylic acid derivatives share the acyl group and react by nucleophilic acyl substitution: addition to form a tetrahedral intermediate, then elimination of a leaving group. Reactivity falls from acid chlorides to anhydrides to esters to amides because leaving groups become stronger bases and resonance donation increases. Derivatives convert readily only into less reactive ones.
Practice questions
1. Name the four main classes of carboxylic acid derivative and give the general formula of each. Answer: Acid chlorides RCOCl, acid anhydrides (RCO)₂O, esters RCOOR′ and amides RCONH₂. 2. Why is chloride a better leaving group than methoxide? Answer: Chloride is a much weaker base, because its conjugate acid HCl is a far stronger acid than methanol, so it is more stable on its own. 3. Explain why amides are the least reactive derivatives. Answer: The nitrogen lone pair is strongly delocalised into the C=O, lowering the electrophilicity of the carbon, and NH₂⁻ is an extremely poor leaving group. 4. Can an ester be converted directly into an acid chloride by treatment with chloride ions? Explain. Answer: No; the acid chloride is more reactive than the ester, and chloride is a weak nucleophile while alkoxide is a poor leaving group, so the reaction would run uphill.