EPR of Transition-Metal Complexes
Oxidation state, ligand field and spin-state clues
Lesson 3681 of 4,500 · Advanced Spectroscopy
Learning objectives
- Predict which d-electron configurations are likely to give observable EPR spectra
- Use g anisotropy and metal hyperfine structure to infer ground-state orbital and geometry
- Recognise superhyperfine coupling as evidence for ligand identity and covalency
Introduction
For inorganic and bioinorganic chemists, EPR is one of the most direct probes of a metal centre. Only paramagnetic states are detected, so the spectrum immediately filters out diamagnetic components of a mixture. The g values, the metal hyperfine pattern and any extra splitting from ligand nuclei together reveal the oxidation state , the spin state and the geometry around the metal. This page brings together g anisotropy, hyperfine coupling and zero-field splitting to read metal complexes.
Core explanation
Is the ion likely to be observable? Start by counting d electrons and deciding the spin state. Systems with an odd number of unpaired electrons are Kramers systems and usually give spectra, although fast relaxation may require cooling to liquid-helium temperatures. Integer-spin ions often need special conditions. A useful first sort:
- Usually easy (S = ½): Cu(II) d⁹, VO²⁺ (V(IV)) d¹, low-spin Fe(III) d⁵, low-spin Co(II) d⁷, Ti(III) d¹, Mo(V) d¹. - Observable with ZFS effects: high-spin Mn(II) and Fe(III) (S = 5/2), Cr(III) (S = 3/2), high-spin Co(II) (S = 3/2, needs low temperature). - Often silent at X-band: high-spin Fe(II) (S = 2), Ni(II) (S = 1) in many geometries. - Diamagnetic, no signal: Zn(II) d¹⁰, low-spin Fe(II) d⁶, Cu(I) d¹⁰, Co(III) low-spin d⁶.
A change in the EPR spectrum on adding a reductant or oxidant therefore signals a change in oxidation state; loss of a Cu(II) signal on reduction to Cu(I) is a classic example.
Ground-state orbital from g. Spin–orbit coupling mixes the singly occupied orbital with others, so the order of g values depends on which orbital holds the unpaired electron. For tetragonally elongated or square-planar copper(II), g∥ > g⊥ > 2.0023 identifies d(x²−y²). For d¹ vanadyl ions, all g values are below 2 (typically g∥ ≈ 1.94, g⊥ ≈ 1.98), matching an unpaired electron in d(xy) and a less-than-half-filled shell.
Metal hyperfine. The metal nucleus gives 2I + 1 lines: four for ⁶³,⁶⁵Cu (I = 3/2), eight for ⁵¹V (I = 7/2), six for ⁵⁵Mn (I = 5/2) and eight for ⁵⁹Co (I = 7/2). The line count identifies the metal, and the size of A reflects how much spin remains on the metal. Covalent bonding moves spin onto ligands and reduces A.
Superhyperfine coupling. When spin delocalises onto ligand atoms with magnetic nuclei, each metal line is split further. Four equivalent ¹⁴N donors (I = 1) give 2 × 4 × 1 + 1 = 9 lines. Resolved nitrogen superhyperfine structure on a copper(II) signal is strong evidence for nitrogen coordination and measures metal–ligand covalency.
Spin-state clues for iron. Iron(III) can be high-spin (S = 5/2) or low-spin (S = ½). High-spin haem iron gives g eff ≈ 6 and 2 from zero-field splitting; rhombic non-haem sites give g eff ≈ 4.3. Low-spin iron(III), for example in cytochromes with two strong axial ligands, gives three g values spread widely either side of 2, such as about 2.9, 2.3 and 1.5. The contrasting signatures reveal whether strong-field ligands have forced spin pairing.
Step-by-step reasoning
To interpret a metal-complex spectrum:
1. Convert to g and note whether values lie above or below 2.0023. 2. Decide whether the pattern is axial, rhombic or dominated by effective g values from ZFS. 3. Count metal hyperfine lines to identify the metal nucleus. 4. Look for superhyperfine splitting and count ligand nuclei. 5. Combine the evidence into oxidation state, spin state and likely geometry.
Visual explanation
Sketch a copper(II) frozen-solution spectrum: four evenly spaced small peaks at low field form the g∥ region, followed by a large derivative feature at g⊥. Zoom into the g⊥ feature and draw nine fine ripples on it, the fingerprint of four equivalent nitrogen donors.
Real-world analogy
A detective identifies a visitor by several clues at once: shoe size, accent and handwriting. No single clue is conclusive, but together they point to one person. The g order, hyperfine count and superhyperfine pattern are the clues that together identify a metal site.
Real-world example
Copper(II) complexed with four nitrogen donors, as in copper–porphyrin or copper–imidazole model compounds, shows nine-line nitrogen superhyperfine structure. Biochemists use the same signature to test whether histidine nitrogens coordinate copper in proteins linked to neurodegenerative disease and in copper-dependent oxidases.
Why?
Why does spin delocalisation onto ligands reduce the metal hyperfine coupling? Hyperfine coupling measures spin density at and around the metal nucleus. When covalent bonding shares the unpaired electron with ligand orbitals, less spin remains on the metal, so the metal coupling decreases while ligand couplings appear.
Common misconception
"No EPR signal means no metal is present." Diamagnetic oxidation states, integer-spin ions with large ZFS, strongly coupled metal pairs and fast-relaxing ions at too high a temperature can all be silent. Absence of a signal must be interpreted with care and checked by other methods.
Worked example
Question: A frozen solution at X-band shows g∥ = 2.24 with four hyperfine lines spaced by about 19 mT (roughly 560 MHz), and g⊥ = 2.05 with nine resolved ripples spaced by about 1.4 mT. Interpret the spectrum.
Reasoning: Four lines indicate a nucleus with I = 3/2, consistent with copper. g∥ > g⊥ > 2.0023 points to a d⁹ d(x²−y²) ground state, so copper(II) in a square-planar or elongated octahedral site. Nine superhyperfine lines match four equivalent ¹⁴N donors.
Answer: A copper(II) complex with four equatorial nitrogen ligands and a d(x²−y²) ground state.
Quick check
1. Which is more likely to give an easily observed X-band spectrum at 77 K: copper(II) or low-spin iron(II)? Explain. Answer: Copper(II), because it has one unpaired electron (S = ½), whereas low-spin iron(II) is diamagnetic with no unpaired electrons.
Exam focus
Be able to classify d-electron configurations as EPR-active or silent, link g order to ground-state orbital for Cu(II) and VO²⁺, identify metals from hyperfine line counts and deduce ligand numbers from superhyperfine patterns. Know the high-spin iron(III) effective g values and the contrasting low-spin iron(III) rhombic pattern.
Advanced insight
Parallel-mode EPR, in which the microwave field is aligned parallel to the static field, can detect some integer-spin ions otherwise silent. Magnetically coupled clusters such as iron–sulfur centres give spectra reflecting the total cluster spin: a [2Fe–2S]⁺ cluster is S = ½ with g values near 2.04, 1.94 and 1.89. Advanced pulsed methods then map individual ligand couplings.
Summary
Transition-metal EPR reveals oxidation state through the presence or absence of signals, spin state through g patterns and ZFS, and geometry through the order of g values. Metal hyperfine line counts identify the metal, and superhyperfine splitting identifies coordinated ligand nuclei and measures covalency. Signal absence does not prove absence of metal.
Practice questions
1. How many metal hyperfine lines does a vanadyl (⁵¹V, I = 7/2) complex show? Answer: 2 × 7/2 + 1 = 8 lines. 2. A copper(II) complex shows g⊥ = 2.20 and g∥ = 2.01. What does this suggest about its ground state? Answer: A d(z²) ground state, typical of trigonal-bipyramidal or compressed geometry. 3. An iron protein shows a sharp signal at g ≈ 4.3. What is the likely iron species? Answer: High-spin iron(III) (S = 5/2) in a strongly rhombic site, with E/D close to 1/3. 4. Why does reducing a copper(II) sample to copper(I) remove its EPR signal? Answer: Copper(I) is d¹⁰ with no unpaired electrons, so it is diamagnetic and EPR-inactive. 5. Predict the number of superhyperfine lines from two equivalent ¹⁴N ligands. Answer: 2 × 2 × 1 + 1 = 5 lines in a 1:2:3:2:1 pattern.